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Trajectory of a Home Run

10/26/2016

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I'm sitting on my warm, snuggly couch watching the Cleveland Indians and the Chicago Cubs in Game 2 of the World Series. The players, coaches, and fans are shivering on my television screen. Today, we are going to discuss the physics of home runs; unfortunately, the cold weather makes it unlikely anyone will hit a dinger in tonight's game. This phenomenon is rooted in fluid dynamics. Cold air has a higher density which results in increased drag on the ball. However, that discussion is outside the scope of this article. 

We are going to investigate how launch angle impacts whether you fly-out or jog around the bases. Recall that the trajectory of a falling object is parabolic; meaning, it has an x- and a y-component. Knowing that distance travelled by a falling object is related to the initial velocity (v), we can mathematically express each component of the velocity utilizing concepts from trigonometry:
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We get the following expressions after plugging the expressions above into the formulas for a zero launch angle:
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Now we can really start digging into our problem. Let's make the following assumptions:
  • The distance from home plate to the fence (x-component) is 400 ft (120 m).
  • The height of the fence (y-component) is 10 ft (3 m).
  • The velocity (v) of the ball is constant at 80 mph (35 m/s).

You may notice we don't have a time component, which is a problem since we have 3 unknowns and two equations. However, we can overcome this by reframing our question: How far has the ball travelled when it reaches a height of 3 m? We ask this question because we want to find the ideal launch angle to hit a home run. So the mechanics look like this:
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Therefore, under the assumed conditions a launch angle of 45 degrees would result in a home run! Let's look at a range of angles to find the "sweet spot:"
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It appears when the ball is traveling at 35 m/s the ideal launch angle is between 45 and 50 degrees. The next question is: How would this change with varying initial velocities?
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As expected, you have greater flexibility of launch angle with increasing velocity. So if you want to crush the ball, you better start pumping iron!
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Exit Velocity vs. Pitch Speed

10/13/2016

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This week we find ourselves in the middle of the Major League Baseball (MLB) Post Season. In the flurry of excitement we hear commentators spouting off different stats. Since everyone "digs the long ball" you better believe you are hearing exit velocity and pitch speed stats.

The exit velocity is the speed of the ball coming off the bat and - quite obviously - the pitch speed is the speed of the incoming throw from the pitcher. These stats are important elements of predicting the characteristic of the hit ball, particularly the ball's distance travelled. However, there has been much debate on the importance of pitch speed on the ultimate exit velocity. Some argue the faster the ball comes in the faster the ball will go out. However, this is not the case. To understand the impact of pitch velocity we need to look at the momentum of the ball.

In this system we consider the forces acting on the ball. Consider the set-up below:
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The impulse (I) is the average force (Fav) delivered to the ball over time (delta t). This is also considered the change in momentum (delta p). The change in momentum can also be expressed as the initial momentum subtracted from the resulting final momentum. When we combine these two equations with the formula for momentum (mass multiplied by velocity) we see a relationship between the force delivered by the batter (Fav) and the speed of the pitch (vpitch). Since we are primarily interested in how these pieces interact to influence the exit velocity, let's isolate the exit velocity:
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You may be thinking to yourself, "Whoa, the pitch velocity is added to the force applied by the batter. So faster pitches should lead to faster exit velocities." However, I would remind you to remember our coordinate system. If our pitch velocity is 90mph, we would write vpitch = - 90mph since it is traveling in the negative x direction. Therefore, pitch velocity decreases the ultimate exit velocity.

To give you an example, let's assume two pitches are thrown and the batter applies the same force to each pitch. How would the exit velocity differ? (We will assume the Fav term will equal 200mph for the ease of the example.)
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This phenomenon can be observed in the MLB stats. Visit Statcast to see that some of this season's hardest hit balls were on relatively slow pitches. Another theory MLB player's have is that since the ball is traveling slower the batter has a better chance at hitting the ball square. There is some truth to this in the likelihood of turning a pitch into a "dinger." However, the physics shows us that if both balls are hit in the same manner that the ball hit off the slower pitch will go faster.

​Enjoy the rest of the Post Season with this tidbit of information. Ask your friends watching the game what they think would result in a harder hit ball, then impress them with your insight.

Go Cubs! :P
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Why on Earth is Gravity Positive?!

9/21/2016

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So you're working hard on your physics homework and you go to check your answers. You notice the answer key has your same answer... But with the opposite sign. What's the deal with that? Gravity is always negative, isn't it? Positive gravity? Why?! How?! Well young physics student, you are forgetting a very important physics rule: always define your coordinate system!

Huh? What's that?

The coordinate system defines the cardinal directions of your problem. They are typically labelled as x, y, and z with the direction of the arrow indicating the positive direction. In your math courses you pretty much always see it like this:
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However, in physics you are free to define the directions in anyway you see fit. This means you can define your coordinate system in such a way that the signs and numbers are simple. So you might end up with a coordinate systems like this:
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Okay, but what does this have to do with positive gravity? Let's look at an example!

You are standing on a cliff and kick a ball off of it. It free falls for 8 seconds. How far has the ball fallen?
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Some textbooks have a negative sign in front of the gravity term and make you memorize that it is for a specific coordinate system and that gravity is always positive, yada yada yada. I find it much easier to pay attention to your coordinate system and keep all the terms in the formula positive. Your numbers will work themselves out and makes you think about what's going on.

Good luck on the rest of your homework!
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A Physics Lesson from a Ketchup Bottle

8/31/2016

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It happens to all of us. We reach into the fridge and pull out the ketchup bottle only to that find the remainder of ketchup is clinging for dear life at the bottom of the bottle. There are two well known practices of getting the remainder of the ketchup out of the bottle. Either you place the bottle on its head and wait for gravity to do its job, or you shake the ketchup down. But, I'm here to tell you there is a third and more efficient way to get that last bit of ketchup out of the bottle.
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Hold the bottom of the ketchup bottle and make sure the lid is secured tightly. Then swing your arm around in a quick circle a few times. When you stop all of the ketchup should be at the top of the bottle. How does this work? Centripetal and centrifugal forces!
Centripetal force is plainly defined at the force exerted on an object towards the center when moving in a circular motion. Centrifugal force is the opposing force exerted on an object to move it away from the center. Both of these forces are required to understand what is happening in our ketchup bottle.
It is helpful to break the bottle and the ketchup into their own force diagrams while maintaining the rotating reference frame. Since you are holding onto the bottle, your hand is exerting the centripetal force necessary to keep the bottle on its circular path. However, there is nothing holding onto the ketchup. Therefore, the centripetal force acting on the ketchup is zero. 
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This causes an unbalanced force to act on the ketchup. Remember what Newton's First Law states? "An object at rest tends to stay at rest and an object in motion tends to stay in motion in the same direction and speed unless acted upon by an unbalanced force." Therefore, the ketchup accelerates away from the center of circular motion until it hits the lid, which subsequently exerts the centripetal force towards the center of the circular motion to stop the flow of ketchup.

Give this technique a "whirl" the next time you need to get the remaining bit of ketchup out of the bottle and impress your friends and family with your knowledge of Physics!
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Music to Your Ears

8/5/2016

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Have you ever wondered what causes your favorite instrument to create sound? The answer is rooted in the physics of waves. There are many different types of waves: transverse, longitudinal, and standing. Transverse waves move perpendicular to the direction of the wave, longitudinal waves move parallel to the direction of the wave, and standing waves appear stationary in space. 
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Basic elements that define a wave are its wavelength, period/frequency, and speed. A wavelength (w) is the distance over which a wave repeats itself. The period (T) is the time required for a single wavelength to pass a defined point. The frequency (f) is inversely related to the period. Finally, speed (v) is the same as if we were referring to the speed of a car: the amount of distance covered over time.
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​Instruments produce sounds via standing waves. Standing waves are composed of nodes (the point at which the wave appears to have zero displacement) and antinodes (the point at which the wave appears to have maximum displacement). The frequency - otherwise known as a harmonic for standing waves - is determined by the fundamental (first) harmonic. Consider part of the derivation shown below.
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So what does any this have to do with instruments? Consider a guitar. It is composed of strings of varying weight, length, and tension. In a string, the wave speed (v) is dependent on the mass per length (m) and tension (F), as shown in the equation at right. ​
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Substituting the equation for the speed of a wave in a string into the equation for the frequency of a standing wave, you find that the frequency of a standing wave depends on the weight, length, and tension of the string, as shown at right. Higher frequencies cause higher pitches. Likewise, lower frequencies cause lower pitches. Therefore, the frequency of the string plucked changes when you adjust string tension when tuning a guitar, or changing the length of the string by moving your finger along the neck.
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So, at your next jam session you can impress your friends with both your musical skills and Physics knowledge.
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